In an isosceles triangle CDE with base CE and angle D equal to 102 degrees, the height CH is drawn.

In an isosceles triangle CDE with base CE and angle D equal to 102 degrees, the height CH is drawn. Find the angle DCCH.

The angle CHD and CDE are adjacent angles, the sum of which is 180, then the angle CDH = 180 – CDE = 180 – 102 = 78.

Since CH is the height of the triangle CDH, then the triangle CDH is rectangular, then the angle DCH = 180 – 90 – 78 = 12.

Answer: The angle DCH is 12.



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