In an isosceles triangle MNK, angle N = 120 °, height KL = 13cm Find the length MN.

The angle LNK will be equal to:

LNK = 180 – MNK = 180 – 120 = 60 degrees.

The NLK triangle is rectangular since KL is the height. Then:

| NK | = | KL | / sin (LNK) = 13 / sin (60) = 26 / √3.

Since the triangle is isosceles (according to the problem statement):

| MN | = | NK | = 26 / √3.



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