In an isosceles triangle MNK, with base MK, the inner angle at the bases is 5 times the other

In an isosceles triangle MNK, with base MK, the inner angle at the bases is 5 times the other inner angle. Find all the corners of the triangle.

According to the condition of the problem, we are talking about the fact that the angle at the base is 5 times the angle at the apex. We introduce the coefficient of proportionality x and we find that the internal angles of an isosceles triangle are equal: 5x, 5x, x. Since the sum of the angles of the triangle is 180 °, we get the equation:
5x + 5x + x = 180
11x = 180
x = 16.363636 ° – angle at the apex of an isosceles triangle;
5x = 5 * 16.363636 = 81.818181 ° – angle at the base.
16.363636 ° ≈ 16.4 °;
81.818181 ° ≈ 81.8 °.
Not very “pretty” answers were obtained, possibly in the condition there is a typo.
If the angle at the base were 4 times larger, then it would be like this:
4x + 4x + x = 180
9x = 180
x = 20 °
4x = 80 °.
We write down our results.
Answer: angles of an isosceles triangle: 81.8 °, 81.8 °, 16.4 °.