In an isosceles triangle, one side is 25 cm long and the other 10 cm. Prove that a side equal to 10 cm cannot be a side.

The conditions for constructing a triangle states that the sum of any two lengths of the sides of the triangle must be greater than the length of the third side.

If AB = BC = 10 cm, then AB + BC = 10 + 10 = 20 cm.

20 <25.

(AB + BC) <AC, which does not meet the conditions for constructing a triangle, therefore, the sides cannot be 10 cm long, which was required to be proved.



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