In an isosceles triangle, the ABC of the base is 16 cm and the lateral side is 10 cm. Find the area of the triangle.

1. The area of a triangle is equal to half the product of the length of the base and the length of the height.

Therefore, to calculate it from the vertex B to the base of the AC, we draw the height BH, which in an isosceles triangle is also the median, dividing the base into two identical segments. That is, AH = CH = AC: 2 = 16: 2 = 8 cm.

2. We calculate the length of the BH height using the formula of the Pythagorean theorem:

BH = √BC ^ 2 – CH ^ 2 = √10 ^ 2 – 8 ^ 2 = √100 – 64 = √36 = 6 cm.

3. The area of the triangle ABC = AC / 2 x 6 = (16: 2) x 6 = 48 cm ^ 2.