In an isosceles triangle, the angle opposite to the base is 2 times greater than the angle at the base

In an isosceles triangle, the angle opposite to the base is 2 times greater than the angle at the base. Find the corners of the triangle.

Let’s solve this problem using the equation.
Let the angles at the base of an isosceles triangle be x degrees, then the angle opposite the base is 2 * x degrees. We know that the sum of the degree measures of a triangle is 180 degrees. Let’s make the equation:
2 * x + x + x = 180;
x * (2 + 1 + 1) = 180;
x * 4 = 180 (in order to find an unknown factor, you need to divide the product by a known factor);
x = 180: 4;
x = 45 degrees – angles at the base;
45 * 2 = 90 degrees – the angle opposite to the base.
Answer: 45 degrees; 45 degrees; 90 degrees.