In an isosceles triangle, the base angle is 54 degrees. How many degrees is the angle of this triangle opposite to the base.

To solve the problem, we will use the property that in an isosceles triangle the angles located at the base are equal. Based on this, we find the sum of the angles at the base:

54 + 54 = 108 (degrees).

Let’s find the angle of the triangle, which is located against the base, taking into account the fact that the sum of all the angles of the triangle is 180 degrees:

180 – 108 = 72 (degrees).

Answer: The angle of the triangle opposite the base is 72 degrees.