In an isosceles triangle, the base angle is 58 degrees. Find the rest of the corners.

In an isosceles triangle, the base angle is 58 degrees. Find the rest of the corners. In an isosceles triangle, the angle opposite to the base is 110 degrees. Find the corners at the base.

Consider a triangle ABC.

By condition ABC is isosceles and AC = BC. In an isosceles triangle, the angles at the base are equal.

1) angle A = 58 °. So B = A = 58 ° and C = 180 ° – A – B = 180 ° – 58 ° – 58 ° = 64 °.

2) angle C = 110 °. So A + B + 110 ° = 180 °, 2 * A = 70 °, A = 35 °.

A = B = 35 ° and C = 110 °.



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