In an isosceles triangle, the base is 1.2 cm less than the lateral side. Find the sides of this triangle

In an isosceles triangle, the base is 1.2 cm less than the lateral side. Find the sides of this triangle if its perimeter is 12.6 cm.

1. Let the length of the base of an isosceles triangle be x cm. It is known that the base is 1.2 cm less than the lateral side, which means that the length of the lateral side is (x + 1.2) cm.

2. The perimeter of a triangle is the sum of the lengths of all its sides. We are given an isosceles triangle, the sides of which are equal in length. This means that the perimeter of this triangle is [x + 2 * (x + 1,2)] cm.

3. It is known that the perimeter of this triangle is 12.6 cm. Let’s write the equality:

x + 2 * (x + 1.2) = 12.6;

3 * x + 2.4 = 12.6;

3 * x = 10.2;

x = 10.2 / 3 = 3.4;

4. We got that the length of the base is 3.4 cm, which means that the length of the lateral side is 3.4 + 1.2 = 4.6 cm.

Answer: the lengths of the sides of the triangle are 4.6 cm, 4.6 cm and 3.4 cm.



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