In an isosceles triangle, the height drawn to the base is 7 cm, and its lateral side is 14 cm. Find the largest angle of the triangle.

1. Vertices of the triangle – A, B, C. AB = BC = 14 centimeters. ВН – height drawn to

base.

2. In a right-angled triangle ABН, the height of the ВН is a leg, and the side of the triangle

AB – hypotenuse. The length of the hypotenuse is 2 times the length of the leg (14: 7 = 2).

Therefore, ∠ВАН (∠А) = 30 °.

3. According to the properties of an isosceles triangle, the angles at its base are equal.

Therefore, ∠ A = ∠C = 30 °.

4. We calculate the value of ∠В:

∠В = 180 ° – ∠А – ∠С = 180 ° – 30 ° – 30 ° = 120 °.

∠В = 120 ° – the largest of all the angles of the triangle.

Answer: the largest angle of the triangle is ∠B = 120 °.



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