In an isosceles triangle, the hypotenuse is 7√2 cm, find the area of the triangular.
| August 8, 2021 | education
Let’s draw the altitude АН to the hypotenuse ВС.
Since AB = AC, the height of AH is also the median of the triangle ABC and the bisector of angle B.
Then AH ^ 2 = BH * CH = ((7 * √2) / 2) * ((7 * √2) / 2) = 49/2.
AH = 7 / √2 cm.
Determine the area of the triangle ABC.
S = BC * AH / 2 = (7 * √2 * 7 / √2) / 2 = 49/2 = 24.5 cm2.
Answer: The area of the triangle is 24.5 cm2.
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