In an isosceles triangle, the lateral side is 20 cm high and lowered to the base of 16 cm, find the base.

univerkov | November 29, 2020 | education

Given:
Triangle ABC
AB = BC = 20 cm
ВH = height = 16 cm
To find:
AC =? cm
Decision:
Consider the triangle ABН = ВСН:
angle AНВ = 90 degrees
According to Comrade Pythagoras:
20 ^ 2-16 ^ 2 = AH ^ 2
AH = 12 cm
AC = 12 * 2 = 24 cm
Answer: 24 cm

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