In an isosceles triangle, the lateral side is twice the height. Find the corners of the triangle.

Let’s call the triangle ABC, then AB and BC are the sides, AC is the base of the triangle, VK is the height. Since the properties of an isosceles triangle say that the height divides the groan into two equal parts, we have two identical right-angled triangles, we denote the leg VK – x, AB – 2x, then sina = x / 2x = 1/2, angle a = 30 degrees, since the angles at the base of an isosceles triangle are always equal, then b = 30 degrees, angle c:
180 – 2 * 30 = 120 degrees.
Answer: 30, 30, 120 degrees.