In an isosceles triangle, the outside angle at the apex opposite to the base is 130 °. Find the angles of this triangle.

The angles adjacent to the base of an isosceles triangle are equal. Since the sum of all the angles of the triangle is 180 degrees, then for the sum of the angles at the base it remains:
180 g – 130 gr. = 50 gr.

Each of the corners at the base is 50 degrees. / 2 = 25 gr.

Answer: 25 gr.

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