In an isosceles triangle, the sides are 8 cm and 5 cm. Find the perimeter of the triangle.

By the condition of constructing a triangle, the sum of the lengths of any two of its sides is greater than the length of the third side.

Since 5 + 5> 8, the problem has two solutions.

1 Let AB = BC = 8 cm and base AC = 5 cm.

Then Ravs = (8 + 8 + 5) = 21 cm.

2 Let AB = BC = 5 cm and base AC = 8 cm.

Then Ravs = (5 + 5 + 8) = 18 cm.

Answer: The perimeter of triangle ABC is 21 cm or 18 cm.



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