In an isosceles triangle, the sum of all angles is 180 °. Find the angles of this triangle if you know that one of them is 38 °.

1) An angle of 38 ° lies at the base of this isosceles triangle.

Since this triangle is isosceles, then its angles at the base and are equal and the second angle at the base is also 38 °.

Since the sum of the angles of any triangle is 180 °, the value of the angle lying opposite the base of this isosceles triangle is 180 – 38 – 38 = 180 – 76 = 104 °.

Therefore, in this case, the angles of the triangle are 38 °, 38 ° and 104 °.

2) An angle of 38 ° lies opposite the base of this isosceles triangle.

Then the sum of two equal angles at the base will be 180 – 38 = 142 °.

Therefore, the angle at the base will be 142/2 = 71 °.

Therefore, in this case, the angles of the triangle are 71 °, 71 ° and 38 °.