In an isosceles triangle, the sum of the two angles is 108 degrees find the angles of the triangle.

Let’s denote the angles of the triangle: ∠1, ∠2, ∠3.

The sum of all angles in any triangle is 180 °:

∠1 + ∠2 + ∠3 = 180 °.

We substitute the data from the condition into the equation: ∠1 + ∠2 = 108 °, we get:

108 ° + ∠3 = 180 °,

∠3 = 180 ° – 108 °,

∠3 = 72 °.

Since the triangle is isosceles, then ∠1 = ∠2. Means:

∠1 = ∠2 = 108: 2 = 54 °.

Answer: 54 °, 54 °, 72 °.