In an isosceles triangle with a perimeter of 60 cm. Lateral side is 5/2. Find the sides of the triangle.

Let’s denote the triangle ABC
Consider ABC: isosceles, AB: BC = 5: 2, P = 60 cm.
Let 5x cm – AB, then AC – 2x.
Because ABC is isosceles, then AB = BC = 5x.
P = AB + BC + AC, which according to the condition of the problem is 60 cm. Let’s make an equation and solve the problem.
5x + 5x + 2x = 60
12x = 60
x = 5 cm
If x = 5, then AB = 5 * 5 = 25cm, BC = AB = 25cm, AC = 2 * 5 = 10cm
Answer: 25cm, 25cm, 10cm.