In an obtuse triangle ABC AC = BC = 8, the height of AH is 4. Find sin ACB.

Since the ABC triangle is obtuse-angled, its height AH intercepts the continuation of the BC side, then the ACH triangle is rectangular, in which we define the sine of the ACH angle.

SinАСН = АН / АС = 4/8 = 1/2.

Angles ACB and ACH are adjacent angles, and since the sines of adjacent angles are equal, then SinACB = SinACH = 1/2.

Answer: The sine of the angle ABC is 1/2.



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