In an oscillatory counter, the inductance of the coil is 0.2 H. The force is 40 mA. Find the magnetic energy of the coil.

To find out the energy of the magnetic field of the presented coil, we use the formula: Wm = 0.5 * L * I ^ 2.

Data: L – coil inductance (L = 0.2 H); I is the current in the presented coil (I = 40 mA = 4 * 10 ^ -2 A).

Let’s make a calculation: Wm = 0.5 * L * I ^ 2 = 0.5 * 0.2 * (4 * 10 ^ -2) ^ 2 = 160 * 10 ^ -6 J.

Answer: The energy of the magnetic field of the presented coil should be 160 μJ.