In angle ABC, angle B is obtuse, AD is the median. Prove that the ADC angle is greater than the DAC angle.
| November 27, 2020 | education
Let’s deal with this task. Given: ABC – triangle ∠B obtuse AD – median Prove: ∠ADC> ∠DAC Solution: ∠ADC is more obtuse, it follows that it is greater than ∠ABC, which is obtuse by condition. ∠DAC is less than spicy, it follows that it is less than ∠BAC, which by condition is spicy. Q.E.D.
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