In buckwheat, grain size is determined by the interaction of two alleles of one gene, and color is determined by the interaction of two other alleles. When crossing plants with light grains, splitting appeared in F1: 1 part with dark grains, 2 parts with light ones, 1 part with white ones. It is known that half of the plants had large grains, and half had small grains. Calculate the percentage of plants (%) with light, small seeds.
Let A – large seeds, a – small. For alleles of color B – dark, b – white. But the appearance of the phenotype light seeds indicates incomplete dominance. If the splitting in size is 1: 1, then the genotype for the size of the seeds is Aa and aa. Splitting by color – genotype – Bb.
RR W AaBb (c.s.) x M aaBb (m.s.)
g F / M aB ab
AB AaBB (c.t.) AaBb (c.s.)
Av AaBb (c.s.) Aabb (c.b.)
aB aaBB (m.t.) aaBb (m.s.)
av aaBb (m.s) aabb (m.b)
c.c. – 2;
Ph.D. – one;
k.b – 1 ;.
m.t. – one;
mb – 1.
This means that the proportion of plants with small light seeds is 2/8 or 25%
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