In cats, black coat (A) predominates over fawn, and short coat (B) over long coat. Homozygous cats were crossed

In cats, black coat (A) predominates over fawn, and short coat (B) over long coat. Homozygous cats were crossed: Persian (black long-haired) with Siamese (fawn short-haired). The resulting hybrids were then crossed with each other. A. What is the probability of getting a homozygous Siamese kitten in F2? B. How many different genotypes should F2 hybrids have? Q. What is the probability of getting a kitten phenotypically similar to a Persian in F2? D. How many different phenotypes can be expected in F2? E. What is the probability of getting a long-haired field kitten in F2?

According to the designations introduced in the problem statement, we write down homozygous Persian cats with black long hair as AAbb, and Siamese cats with short fawn hair as aaBB. The former produces the same type of sex cells Ab, the latter – aB.

From crossing such cats, all the resulting offspring of kittens will be AaBb, which corresponds to black short hair. Such hybrids produce sex cells AB, AB, AB, and AB.

The offspring from crossing such cats with each other looks as follows:

kittens with black short hair (AABB, 2AaBB, 2AABb, 4AaBb);

kittens with black long hair (2Aab, AAbb);

kittens with fawn short hair (aaBB, 2aaBb);

kittens with fawn long hair (aabb).

A) Probability of a homozygous Siamese kitten in F2 (aaBB): 1 genotype out of 16, or 6.25%;

B) 16 different genotypes;

C) The probability of a Persian kitten in F2: 3 genotypes out of 16, or 18.75%;

D) 4 different phenotypes;

E) Long-haired fawn kitten (aabb) – 1 genotype out of 16, or 6.25% probability.