In convex quadrilateral ABCD, diagonal BD bisects angle B. BD2BC = AB. Prove that BAD = BDC.
| February 8, 2021 | education
By the condition <DBC = <ABD, as the angles that are divided by equal to the diagonal BD; AB = BC by condition. Consider triangles ABD and DBC.
In them, two sides are equal: AB = BC (by condition), side BD is common (that is, the second equal side). Angle between equal sides of one triangle ABD, <ABD = <DBC. the angle between two correspondingly equal sides of another triangle, BCD.
This means that the triangles BAD and BDC are based on the equality of two sides and the angle between them. Q.E.D.
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