In equilateral triangle ABC the height АН and the median ВМ are drawn. They crossed at point O. Find the AOB.

Since in an equilateral triangle, each angle is 60 °, and from the properties of an equilateral triangle, we know that the median (drawn from point B) and height (drawn from point A) are both bisectors, we find out that the angles OAB and OBA are 30 ° each.

Having the values of two angles in the ABO triangle, we calculate the third angle.

From the properties of triangles, we know that the sum of the angles is 180 °.

180 – 30 – 30 = 120.

Answer: angle AOB = 120 °.



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