In equilibrium, a force of 100n acts on its smaller shoulder, and a force of 10n on the large one.

In equilibrium, a force of 100n acts on its smaller shoulder, and a force of 10n on the large one. the length of the smaller shoulder is 4 cm. determine the length of the large shoulder

Initial data: the lever is in equilibrium; F1 (force on the smaller arm of the lever) = 100 N; F2 (force on the larger arm) = 10 N; l1 (length of the smaller shoulder) = 4 cm.

We express the length of the larger shoulder from the equality: M1 = F1 * l1 = F2 * l2 = M2, whence l2 = F1 * l1 / F2.

Calculation: l2 = 100 * 4/10 = 40 cm.

Answer: The length of the larger shoulder is 40 centimeters.