In humans, the brown-eyed gene dominates over the blue-eyed gene. Determine and write down

In humans, the brown-eyed gene dominates over the blue-eyed gene. Determine and write down in gene expression the probability of having blue-eyed children in the following cases: a) both parents are homozygous for brown-eyed; b) both parents are heterozygous; c) one parent is heterozygous, and the other is blue-eyed.

Let’s designate the dominant gene that causes brown-eyed as C, then the blue-eyed gene will be designated as c.

a) Both parents are homozygous for brown eyes – CC. They produce the same type of sex cells C. All offspring in such a family will be homozygous for brown-eyed – CC and have the corresponding phenotype – brown eyes;

b) Both parents are heterozygous – Cc. They both produce sex cells with and C. In the offspring, options are possible: CC – 25% (brown eyes), Cc – 50% (brown eyes), cc – 25% (blue eyes).

c) One parent is heterozygous – Cc (germ cells – c and C), the second parent of blue-eyed – cc (germ cells – c). The offspring are represented by options: Cc – 50% (brown eyes), cc – 50% (blue eyes).