In humans, the gene for long eyelashes dominates over the gene for short eyelashes. A woman with long eyelashes

In humans, the gene for long eyelashes dominates over the gene for short eyelashes. A woman with long eyelashes, whose father had short eyelashes, married a man with short eyelashes. 1) How many types of gametes does a woman have? 2) How many types of gametes do a man have? 3) What is the likelihood of a child with long eyelashes in this family? 4) How many different genotypes and how many phenotypes can there be among the children of a given married couple?

A – long eyelashes, a – short eyelashes.
Since the woman’s father was with short eyelashes, that is, homozygous for the recessive trait, the woman with long eyelashes has the genotype Aa (heterozygous). Her husband, like her father – aa.
Splitting by genotype in children will be Aa: aa, 1: 1. By phenotype, long eyelashes: short eyelashes 1: 1.
Answer: a woman develops 2 types of gametes; a man forms 1 type of gametes; the probability of having children with long eyelashes is 50%; among the children of a given married couple, there can be 2 different genotypes (Aa, aa) and two different phenotypes (long eyelashes, short eyelashes).