In isosceles triangle ABC with equipment BC, point E is marked on the median AD.

In isosceles triangle ABC with equipment BC, point E is marked on the median AD. Prove that triangle AEB is equal to triangle AEC.

In an isosceles triangle, the median drawn to the base is the bisector, which means that BP is the bisector of angle A.

Consider triangles AEB and AEC:

AB = AC (triangle ABC isosceles),

AE – common side,

the angle BAE is equal to the angle SAE (since AD is the bisector).

Triangles AEB and AEC are equal in the first sign of equality of triangles (on two sides and the angle between them).



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