In oblique triangular prism ABCA1B1C1, the base is a regular triangle with side equal to a.

In oblique triangular prism ABCA1B1C1, the base is a regular triangle with side equal to a. The side edge is equal to b, ∠A1AC = 1A1AB. The CC1B1B face area is?

In an inclined triangular prism, two of its side faces are parallelograms, and one is a rectangle.
Since, by condition, the angle А1АВ = АА1С, then the faces АА1В1В and АА1С1С are parallelograms, then the face В1С1С is a rectangle.
Since at the base of the prism there is a regular triangle, then AB = BC = AC = a cm.
Then Scc1v1s = AC * CC1 = a * b cm2.
Answer: The area of the CC1B1B face is equal to a * b cm2.



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