In one cycle, the heat engine received an amount of heat of 10 J from the heater and gave it to the refrigerator 6 J.

In one cycle, the heat engine received an amount of heat of 10 J from the heater and gave it to the refrigerator 6 J. What is the efficiency of the machine?

The machine received 10 J of energy from the heater, and gave the refrigerator only 6 J, during the transfer the car lost 4 J of energy, we calculate the efficiency in percentage:
(6:10) * 100% = 60% (Final energy, divide by the initial and multiply by 100 percent)
Answer. Efficiency – 60%



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