# In one family, brown-eyed parents have four children. Two blue-eyed have 1 and 4 blood groups

In one family, brown-eyed parents have four children. Two blue-eyed have 1 and 4 blood groups, two brown-eyed 2 and 3. Determine the likelihood of the next child with brown-eyed blood group 1. Brown eye color is dominant over blue and is due to an autosomal gene.

If brown-eyed parents have children with blue ones, then they are heterozygous to the given trait. The offspring with all possible blood groups are given by parents with 2 and 3 blood groups, who are also heterozygous.

Parents: AaI (A) I (0) × AaI (B) I (0)

Gametes: AI (A) AI (0) A (I (B) AI (0)

aI (A) aI (0) aI (B) aI (0)

Prospective offspring: AAI (A) I (B) brown eye color, group 4, AAI (A) I (0) brown eye color, group 2, AaI (A) I (B) brown eye color group 4, AaI (A ) I (0) brown eye color, group 2, AAI (B) I (0) brown eye color, group 3, AAI (0) I (0) brown eye color, group 1, AaI (B) I (0) brown eye color, group 2, AaI (0) I (0) brown eye color, group 1, AaI (A) I (B) brown eye color, group 4, AaI (A) I (0) brown eye color, 2 group, aaI (A) I (B) blue eye color, group 4, aaI (A) I (0) blue eye color, group 2, AaI (B) I (0) brown eye color, group 3, AaI (0 ) I (0) brown eye color, group 1, aaI (B) I (0) blue eye color, group 3, aaI (0) I (0) blue eye color, group 1. Of the 16 genotypes, brown eye color and the first blood group occur three times, respectively, the probability of having such a child is 18.75%.

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