In one magnetic field with an induction of 0.25 T there is a 1.4 m rectilinear conductor on which a force of 2.1

In one magnetic field with an induction of 0.25 T there is a 1.4 m rectilinear conductor on which a force of 2.1 N acts. determine the angle between the direction of the current in the conductor and the direction of the magnetic field, if the current in the conductor is 12A

Let us write down a short statement of the problem.

Given:

L = 1.4 m;

F = 2.1 H;

I = 12 A;

B = 0.25 T;

α -?

An ampere force acts on a conductor with a current located in a magnetic field. It is calculated by the formula:

F = I * B * L * sіnα, where α is the angle between the lines of magnetic induction and the direction of the current in the conductor.

Let us express the sine of the angle from this formula, we get:

sіnα = F / (I * B * L).

Substitute all known quantities (numerical values) into the resulting formula and find it:

sіnα = 2.1 N / (12 A * 0.25 T * 1.4 m) = 2.1 H / 4.2 H = 1/2.

Using the Bradis table, knowing the sine of the angle, we determine the angle itself.

We get:

α = 30º.

Answer: α = 30º.