In order to cool the piece machined from copper, which has a temperature of 100 ° C, it was immersed

| March 1, 2021 | education

In order to cool the piece machined from copper, which has a temperature of 100 ° C, it was immersed in water weighing 679 g and a temperature of 20 ° C. Determine the mass of the part if it is known that during the heat exchange the water has heated up to 25 ° C.

Given: t1 (part temperature after manufacturing) = 100 ºC; m2 (mass of water) = 679 g (0.679 kg); t2 (water temperature) = 20 ºC; t (temperature after heat exchange) = 25 ºC.

Constants: C1 (specific heat capacity of copper) = 400 J / (kg * ºC); C2 (specific heat capacity of water) = 4200 J / (kg * ºC).

We determine the mass of the machined copper part from the equality: C1 * m1 * (t1 – t) = C2 * m2 * (t2 – t), whence m1 = C2 * m2 * (t2 – t) / (C1 * (t1 – t)) …

Calculation: m1 = 4200 * 0.679 * (25 – 20) / (400 * (100 – 25)) = 0.4753 kg (475.3 g).



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