In parallelepiped ABCD, point K is the midpoint of side AD, and point L is the midpoint of side BC

In parallelepiped ABCD, point K is the midpoint of side AD, and point L is the midpoint of side BC, and KBLD is a rectangle with an area of 20 (m2). Find the area of parallelogram ABCD.

consider 2 triangles: ВAK and LCD, they have ВK = LD, since the opposite sides of the rectangle are equal; respectively, kut L = kutu K and kut kut B = kutu D, as external versatile (there is a rule, when 2 parallels, then external versatile kuta They are even). Now 2 triangles, with the same side and two identical kutas are considered equal. Since AK = KD according to the task data, and KD = LD, as the sides of a rectangle, then the area of AВСD = S ВAK + SLCD + SKBLD as a result: 20 + 20 + 20 = 60 square meters