In parallelogram ABCD, angle 1 = 40 degrees BC is parallel to AD, BK is parallel to DC. Find angle 2.
| September 16, 2021 | education
Since, according to the condition, ВK is parallel to DC, then the angle 1 = ВСD = KBC as criss-crossing angles at the intersection of parallel lines AB and CD of the secant CB, then the angle KBC = 40.
BN is parallel to AD, therefore, the angle NBC is unfolded and equal to 180. Then the angle NBK = NC – KBC = 180 – 40 = 140.
Answer: Angle 2 is 140.
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