In parallelogram ABCD, angle B is 150 degrees AD is 10 cm AB is 8 cm. Find the area of the parallelogram.

1. According to the condition of the problem, the angle B is equal to 150 *, the internal one-sided angles A and B with parallel BC and AD total 180 *, which means that the angle A = 180 * – angle B = 180 * – 150 * = 30 *.

2. Using the sine of the angle at 30 * and the hypotenuse AB, equal to 8 cm, we find the height of the parallelogram h, which in this case is the leg.

h: AB = sin 30 *;

h = sin 30 * AB = 1/2 * 8 cm = 4 cm.

3. Let’s calculate the area S of the parallelepiped ABCD.

S = AD * h = 10cm * 4cm = 40cm ^ 2.

Answer: The area of a parallelepiped is 40 square centimeters.