In parallelogram ABCD, angle B is 40 ° greater than angle A. Find the value of angle D.

1. Let us denote the angle by the symbol ∠.

2. ∠В is more than А by 40 ° according to the problem statement. That is, ∠В = ∠А + 40 °.

3. Using the property of a parallelogram that the sum of two angles adjacent to one of its sides is 180 °, we calculate the degree measure ∠A:

∠А + ∠В = 180 °.

∠А + ∠А + 40 ° = 180 °.

2∠A = 140 °.

∠А = 70 °.

4.Calculate the degree measure ∠Д, using the property of the parallelogram that the sum of two angles adjacent to one of its sides is 180 °:

∠D = 180 ° – 70 ° = 110 °

Answer: ∠Д = 110 °