In parallelogram ABCD, angle B is obtuse. Height CF with side CD angle FCD = 60 degrees, AB = 6 cm
| August 7, 2021 | education
In parallelogram ABCD, angle B is obtuse. Height CF with side CD angle FCD = 60 degrees, AB = 6 cm, BC = 10 cm. Find the area of the parallelogram.
Since СF is the height of the parallelogram, then the angle ВСF = 90, then the angle ВСD = ВСF – DCF = 90 – 60 = 30.
In a parallelogram, the opposite sides are equal, then the segment CD = AB = 6 cm.
The area of a parallelogram is equal to the product of its sides by the sine of the angle between them.
Savsd = ВС * СD * Sin30 = 10 * 6 * (1/2) = 30 cm2.
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