In parallelogram ABCD diagonal BD = 9 cm, side DC = 11 cm, BC = 4 cm.Find the perimeter of ABD.

Since the opposite sides of the parallelogram are equal, then AD = BC = 4 cm, AB = CD = 11 cm.

Then the perimeter of the triangle ABD will be equal to: Ravd = AB + AD + BD = 11 + 4 + 9 = 24 cm.

Answer: The perimeter of triangle ABD is 24 cm.



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