In parallelogram ABCD, o is the intersection point of the diagonals. CD = 15 cm, AC = 24cm

univerkov | August 13, 2021 | education

In parallelogram ABCD, o is the intersection point of the diagonals. CD = 15 cm, AC = 24cm, DO = 9cm. Find the perimeter of triangle AOB

Since ABCD is a parallelogram, AB = CD = 15 cm.
Point O divides the segment AC in half, then :, AO = CO = AC / 2 = 24/2 = 12 cm.
BO = DO = 9 cm.
Then: Raov = (AB + BО + AO) = (15 + 9 + 12) = 36 cm.
Answer: The perimeter of the AOB triangle is 36 cm.

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