In parallelogram ABCD, point F lies on the diagonal AC AF: FC = 4: 3. Express the vector BF in terms of the vectors BA = a and BC = b.

vector AC = vector b – vector a;

vector BF = vector a + vector AF;

vector AF = 4/7 * vector AC = 4/7 * (vector b – vector a);

vector BF = vector a + 4/7 * (vector b – vector a);

vector BF = vector a + 4/7 * vector b – 4/7 vector a;

vector BF = 3/7 * vector a + 4/7 * vector b.

Answer: vector BF = 3/7 * vector a + 4/7 * vector b.



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