In parallelogram ABCD, segment AM is the bisector of angle A. Prove that triangle ABM is equilateral.
| June 15, 2021 | education
Since AM is the bisector of the angle BAD, the angle BAM is equal to the angle DAM.
The DAM angle is equal to the BMA angle as intersecting angles at the intersection of parallel straight lines AD and BC of the secant AM.
Then the angle BAM is equal to the angle BAM. If in a triangle the angles at the base are equal, then such a triangle is isosceles, which was required to prove.
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