In parallelogram ABCD, side AB = 12, AD = 15. Find the area of the parallelogram ABCD if cosC = 0.6.

univerkov | November 22, 2020 | education

S = sinA * AD * AB
angle A = C (by the property of a parallelogram)
from trigonometric identity
sinA ^ 2 + cosA ^ 2 = 1
sinA = 0.8
S = 12 * 15 * 0.8 = 144

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