In parallelogram ABCD, side AB = 8 cm, AD = 10, angle BAD = 30 degrees Find the area of the parallelogram.

Let’s lower the height BD to the AD side. In a right-angled triangle ABE, the height BE is opposite the angle BAD = 30:

BE = AB / 2 = 8 cm / 2 = 4 cm.

Parallelogram area:

SABCD = AD * BE = 10cm * 4cm = 40cm ^ 2.

Answer: 40 cm ^ 2.



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