In parallelogram ABCD, side AB is 5√2 and angle B is 135 degrees. Find the height of the parallelogram.

From the vertex B of the parallelogram, draw the height BH.

Determine the angles of a right-angled triangle ABH.

Angle ABM = ABC – HBC = 135 – 90 = 450.

Then the angle BАH = 180 – 90 – 45 = 450.

Then triangle ABH is rectangular and isosceles.

Determine the length of the leg BH.

AB ^ 2 = BH ^ 2 + AH ^ 2 = 2 * BH ^ 2.

BH ^ 2 = AB ^ 2/2 = (5 * √2) ^ 2/2 = 50/2 = 25.

BH = √25 = 5 cm.

Answer: The height of the parallelogram is 5 cm.



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