In parallelogram ABCD, the bisector of an acute angle C intersects side AD at point M

In parallelogram ABCD, the bisector of an acute angle C intersects side AD at point M, AM = 2 cm, MD = 8 cm. Find the perimeter of parallelogram ABCD.

In Figure 3, CM is the bisector of the BCM angle, then it cuts off the isosceles triangle CDM at the lateral side CD, CD = DM = 8 cm.

AD = AM + DM = 2 + 8 = 10 cm.

BC = AD = 10 cm.

AB = CD = 8 cm.

Then Ravsd = 2 * (AB + AD) = 2 * 18 = 36 cm.

Answer: The perimeter of the parallelogram is 36 cm.



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