In parallelogram ABCD, the diagonal AC is 12 cm, and the side AD is 10 cm

In parallelogram ABCD, the diagonal AC is 12 cm, and the side AD is 10 cm, and the CAD angle is 30 degrees. Find the area of the parallelogram.

The AC diagonal divides the parallelogram into 2 identical triangles. Find the area of the triangle ACD. Then we multiply it by 2.

S = (AC * AD * sin30 °) ÷ 2 * 2 = AC * AD * sin30 °.

S = 12 cm * 10 cm * sin30 ° = 120 cm² * 0.5 = 60 cm².

Answer: the area of the parallelogram is 60 cm².



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