In parallelogram ABCD, the diagonals AC and BD are equal. Prove that triangle COD is isosceles.

Since the parallelogram has the AC diagonal equal to the BP diagonal, this parallelogram is a rectangle.

Since the diagonals at the intersection point are divided in half, then AO = CO = BO = DO, then in the triangle COD, CO = OD, and therefore the triangle COD is isosceles, which was required to prove.



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