In parallelogram ABCD, the diagonals are 8 cm and 5 cm, side BC is 3 cm
| April 25, 2021 | education
In parallelogram ABCD, the diagonals are 8 cm and 5 cm, side BC is 3 cm, O is the point of intersection of the diagonals. What is the perimeter of a triangle AOD
ABCD is a parallelogram.
BD = 8 cm.
AC = 5 cm.
BC = 3 cm.
R – ?
1. The perimeter P of a triangle ΔAOD is the sum of all its sides.
P = AO + OD + AD.
2. According to the property of a parallelogram, its opposite sides are equal to each other.
AD = BC.
AD = 3 cm.
3. According to the parallelogram property, the diagonals are halved by the intersection point.
OD = OB = BD / 2.
OD = OB = 8cm / 2 = 4cm.
AO = OC = AC / 2.
AO = OC = 5 cm / 2 = 2.5 cm.
4. Find the perimeter P ΔAOD.
P = 2.5 cm + 4 cm + 3 cm = 9.5 cm.
Answer: The perimeter of the triangle AOD is P = 9.5 cm.
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